Hindi walkthrough of the pointer-flipping trick. We show iterative (preferred for interviews) and recursive (helpful to know). Pointer diagrams, code in 3 languages, and the classic follow-up: reverse only the first K nodes.
Neeche is topic ka Hinglish explanation hai, wahi jo hamare course lesson mein audio narration ke saath chalta hai. Code English mein hai, samjhana Hindi mein.
Linked list reverse karna sabse common pointer manipulation problem hai. Concept mein easy hai aur practice na ho toh brutal. Trick hai teen lines ka order. Galat ho gaya toh list silently break ho jaata hai.
Tumhe diya gaya hai singly linked list ka head. Reverse karna hai aur naya head return karna hai. Original list in-place mutate hota hai. Solve karo iteratively aur recursively dono: interviewer dono poochte hain.
Pattern hai "teen pointers carry karte hue chalo". Previous, current, aur next. Har step pe save karte ho kahaan chain todne waale ho taaki re-link kar sako. Yeh teen pointer dance har jagah aata hai: partition, rotation, K-group reversal.
Pehle iterative code. Loop ke andar teen lines, exact iss order mein. Ek: next save karo. Do: current dot next ko previous pe point karne ke liye flip karo. Teen: previous aur current ek aage shift karo. Inn teen mein se koi do swap kiye toh list break ho jaati hai.
Ab recursive solution. Recurse karo end tak, naya head lo, phir wapas aate hue har pointer flip karo. Base case hai aakhri node, jo naya head banta hai aur upar bubble up hota hai. Do baar padho: linked list pe recursion pehle thoda unintuitive lagta hai.
Dono approaches O(n) time hain. Iterative O(1) space hai. Recursive O(n) space hai call stack ki wajah se: har recursive frame ek pointer hold karta hai. Bahut lambi list ke liye recursion stack-overflow ho sakta hai. Iterative safer hai.
Common follow-ups. Sirf positions m aur n ke beech reverse karo. K ke groups mein reverse karo. List reorder karo. Second half reverse karke palindrome detect karo. In sab problems ka ek common subroutine hai: linked list reverse karna. Iss ko master karo aur saare tractable ho jate hain.
def reverseList(head):
prev, curr = None, head
while curr:
next_node = curr.next # 1. Save the next node first.
curr.next = prev # 2. Flip the current node's pointer backward.
prev = curr # 3. Advance prev to current.
curr = next_node # 4. Advance current to saved next.
return prevComplexity: Iterative: time O(n), space O(1); Recursive: time O(n), space O(n).
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